<feed xmlns="http://www.w3.org/2005/Atom"> <id>https://blog.bienew.me/</id><title>bienew22</title><subtitle>Notes and tutorials on Java, Python, and algorithms for continuous learning.</subtitle> <updated>2026-04-30T17:09:20+09:00</updated> <author> <name>bienew22</name> <uri>https://blog.bienew.me/</uri> </author><link rel="self" type="application/atom+xml" href="https://blog.bienew.me/feed.xml"/><link rel="alternate" type="text/html" hreflang="en" href="https://blog.bienew.me/"/> <generator uri="https://jekyllrb.com/" version="4.4.1">Jekyll</generator> <rights> © 2026 bienew22 </rights> <icon>/assets/img/favicons/favicon.ico</icon> <logo>/assets/img/favicons/favicon-96x96.png</logo> <entry><title>[프로그래머스] 숫자 타자 대회</title><link href="https://blog.bienew.me/posts/programmers-number-typing-competition/" rel="alternate" type="text/html" title="[프로그래머스] 숫자 타자 대회" /><published>2026-04-29T16:00:00+09:00</published> <updated>2026-04-29T16:00:00+09:00</updated> <id>https://blog.bienew.me/posts/programmers-number-typing-competition/</id> <content type="text/html" src="https://blog.bienew.me/posts/programmers-number-typing-competition/" /> <author> <name>bienew22</name> </author> <category term="Problem Solving" /> <category term="Programmers" /> <summary>프로그래머스 '숫자 타자 대회' 문제 풀이</summary> </entry> <entry><title>[프로그래머스] 야근 지수</title><link href="https://blog.bienew.me/posts/programmers-overtime-index/" rel="alternate" type="text/html" title="[프로그래머스] 야근 지수" /><published>2026-04-24T16:00:00+09:00</published> <updated>2026-04-24T16:00:00+09:00</updated> <id>https://blog.bienew.me/posts/programmers-overtime-index/</id> <content type="text/html" src="https://blog.bienew.me/posts/programmers-overtime-index/" /> <author> <name>bienew22</name> </author> <category term="Problem Solving" /> <category term="Programmers" /> <summary>프로그래머스 '야근 지수' 문제 풀이</summary> </entry> <entry><title>[LeetCode] Zigzag Conversion</title><link href="https://blog.bienew.me/posts/leetcode-zigzag-conversion/" rel="alternate" type="text/html" title="[LeetCode] Zigzag Conversion" /><published>2026-04-22T15:00:00+09:00</published> <updated>2026-04-22T15:00:00+09:00</updated> <id>https://blog.bienew.me/posts/leetcode-zigzag-conversion/</id> <content type="text/html" src="https://blog.bienew.me/posts/leetcode-zigzag-conversion/" /> <author> <name>bienew22</name> </author> <category term="Problem Solving" /> <category term="LeetCode" /> <summary>LeetCode 'Zigzag Conversion' 문제 풀이</summary> </entry> <entry><title>[Algorithm] Manacher's Algorithm</title><link href="https://blog.bienew.me/posts/algorithm-manacher/" rel="alternate" type="text/html" title="[Algorithm] Manacher&amp;apos;s Algorithm" /><published>2026-04-19T13:00:00+09:00</published> <updated>2026-04-19T13:00:00+09:00</updated> <id>https://blog.bienew.me/posts/algorithm-manacher/</id> <content type="text/html" src="https://blog.bienew.me/posts/algorithm-manacher/" /> <author> <name>bienew22</name> </author> <category term="Concept Notes" /> <category term="Algorithm" /> <summary>Manacher’s Algorithm? 마나커 알고리즘(Manacher’s Algorithm)은 문자열에서 각 문자를 중심으로 하는 가장 긴 팰린드롬의 길이를 O(N에 찾는 알고리즘입니다. 팰린드롬? 앞으로 읽으나 뒤로 읽으나 똑같은 단어, 문자열, 숫자열 등을 의미합니다. 기호 및 변수 정의 S : 문자열 i : 현재 탐색하는 팰린드롬의 중심 인덱스 P[i] : S[i]를 중심으로 하는 팰린드롬의 반지름 C : 현재까지 가장 오른쪽으로 뻗은 팰린드롬의 중심 R : C에 해당하는 팰린드롬의 반지름 핵심 아이디어 1. 기본 확장 (Brute-force) P[i]를 계산할 때 i 기준으로 좌우를 확장하여 탐색하여 계산합니다. ...</summary> </entry> <entry><title>[프로그래머스] 제곱 개수 배열</title><link href="https://blog.bienew.me/posts/programmers-count-square-numbers/" rel="alternate" type="text/html" title="[프로그래머스] 제곱 개수 배열" /><published>2026-04-10T16:00:00+09:00</published> <updated>2026-04-10T16:00:00+09:00</updated> <id>https://blog.bienew.me/posts/programmers-count-square-numbers/</id> <content type="text/html" src="https://blog.bienew.me/posts/programmers-count-square-numbers/" /> <author> <name>bienew22</name> </author> <category term="Problem Solving" /> <category term="Programmers" /> <summary>프로그래머스 '제곱 개수 배열' 문제 풀이</summary> </entry> </feed>
